# Line slope calculator 2x+4y=50

**Straight line given by points A[5; 10] and B[9; 8]**

## Calculation:

**Slope-intercept form of line:**y = -0.5x+12.5

**Canonical form of the line equation:**2x+4y-50 = 0

**Parametric form of the line equation:**

x = 4t+5

y = -2t+10 ; t ∈ R

**Slope:**m = -0.5

**Slope angle of line: φ =**-26°33'54″ = -0.4636 rad

**X intercept:**x

_{0}= 25

**Y intercept:**y

_{0}= q = 12.5

**Distance line from the origin:**d

_{0}= 11.1803

**The length of the segment AB: |AB| =**4.4721

**Vector: AB =**(4; -2)

**Normal vector: n =**(2; 4)

**Midpoint of the segment AB: M =**[7; 9]

**Perpendicular Bisector equation:**4x-2y-10 = 0

**Vector OA = (5; 10) ; |OA| = 11.1803**

**Vector OB = (9; 8) ; |OB| = 12.0416**

**Scalar product OA .OB = 125**

**Angle ∠ AOB = 21°48'5″ = 0.3805 rad**